Talk:truncated icosahedron

RFD discussion: May 2016
Sum of parts. The translations are redlinks.— Pingkudimmi 09:57, 11 May 2016 (UTC)


 * Keep. There is no way to get "12 regular pentagonal faces, 20 regular hexagonal faces" from truncated and icosahedron. bd2412 T 12:13, 11 May 2016 (UTC)
 * Yes, I think we should keep this one, even though it is a little encyclopedic. SemperBlotto (talk) 12:25, 11 May 2016 (UTC)
 * Withdrawn. Thanks . Although, to be fair, the number of pentagonal faces is the number of vertices of the icosahedron, and the number of hexagonal faces is the number of triangular faces of the same. It's less obvious why they should be pentagons, but the ratio 12:60 of vertices to edges of the icosahedron should give a clue (as well as the fact that the icosahedron and dodecahedron are dual polyhedra).— Pingkudimmi 08:18, 13 May 2016 (UTC)